MHB Can You Solve This Non-Constant Coefficient Difference Equation?

Click For Summary
The discussion centers on solving the non-constant coefficient difference equation $(x+1)y_{x+1}-(r+x)y_{x}+ry_{x-1}=0$, where r is a constant. The standard approach involves rewriting the equation to express y_{x+1} in terms of y_x and y_{x-1}, allowing for a block-wise solution. An initial value for y is necessary, typically defined over a specific range, such as 0 ≤ x ≤ 2. For instance, if y(x) is defined as x in that range, the solution for 2 ≤ x ≤ 3 can be derived as y(x) = (r+x-1)(x-1) - r(x-2)/(x). This method provides a structured way to tackle the equation based on initial conditions.
Poirot1
Messages
243
Reaction score
0
I wish to solve a non constant coefficents difference equation $(x+1)y_{x+1}-(r+x)y_{x}+ry_{x-1}=0$ where r is a constant. Is there a characteristic equation and generic solution for this ?
 
Physics news on Phys.org
Actually, the standard way of solving that would be to write y_{x+1}= [(r+x)y_x- ry_{x-1}]/(x+1) and solve in "blocks". You would have to be given an "initial value" of y on, say, 0\le x\le 2. For example, if you we given that y(x)= x for 0\le x\le 2 then , for 2\le x\le 3 we would have y(x)= (r+x-1)(x-1)- r(x-2)/(x).
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
920
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
0
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K