Can You Solve This Non-Constant Coefficient Difference Equation?

Click For Summary
SUMMARY

The discussion focuses on solving the non-constant coefficient difference equation $(x+1)y_{x+1}-(r+x)y_{x}+ry_{x-1}=0$, where r is a constant. The standard method involves rewriting the equation as $y_{x+1}= [(r+x)y_x- ry_{x-1}]/(x+1)$ and solving in blocks. An initial value for y is required, such as y(x) = x for the interval 0 ≤ x ≤ 2. For the interval 2 ≤ x ≤ 3, the solution is expressed as $y(x)= (r+x-1)(x-1)- r(x-2)/(x)$.

PREREQUISITES
  • Understanding of difference equations
  • Familiarity with characteristic equations
  • Knowledge of initial value problems
  • Basic algebraic manipulation skills
NEXT STEPS
  • Research methods for solving non-constant coefficient difference equations
  • Study the concept of characteristic equations in depth
  • Explore initial value problem techniques in difference equations
  • Learn about block-wise solution strategies for difference equations
USEFUL FOR

Mathematicians, students studying difference equations, and researchers working on numerical methods for solving differential equations.

Poirot1
Messages
243
Reaction score
0
I wish to solve a non constant coefficents difference equation $(x+1)y_{x+1}-(r+x)y_{x}+ry_{x-1}=0$ where r is a constant. Is there a characteristic equation and generic solution for this ?
 
Physics news on Phys.org
Actually, the standard way of solving that would be to write y_{x+1}= [(r+x)y_x- ry_{x-1}]/(x+1) and solve in "blocks". You would have to be given an "initial value" of y on, say, 0\le x\le 2. For example, if you we given that y(x)= x for 0\le x\le 2 then , for 2\le x\le 3 we would have y(x)= (r+x-1)(x-1)- r(x-2)/(x).
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
962
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
0
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K