I Canonical form derivation of (L1'AL1)

[Sanchayan Ghosh]

Hello everyone,

I actually had a problem with understanding the part where they have defined L'AL = Λ. There, they have taken
γΛγ₁ = Σy²λ = 1. Why have they taken that? Is it arbitary or does it come as a result of a derivation?

Thank you

 

[Nguyen Son]

sorry, we cannot see the picture

 

[Sanchayan Ghosh]

I don't know why it got blurred. Actually I resolved the problem.
y'Δy is nothing but mitiplying the transpose of vector components of y with the symmetric matrix
Δ = L'₁AL₁
L is the 1x3 matrix of eigen values of a symmetric matrix A.
And then multiplying the result with y vector. This gives the above expression as I had asked.

Thank you.