- #1
cheechnchong
- 132
- 1
Problem: The Earth orbits the sun once a year (3.16 x 10^7 s) in a nearly circular orbit of radius 1.5 x 10^11 m. With respect to the sun, determine (a) the angular speed of the earth, (b) the tangential speed of the earth, and (c) the magnitude and direction of the Earth's center centripetal acceleration.
My Approach:
(a) Finding Velocity:
V = (1.5 x 10^11 m)/(3.16 x 10^7 s) = 4747 m/s
--I did this because I'm assuming the Earth's orbit of the sun is constant
(b) Tangential Speed:
V = rw = (1.5 x 10^11 m) (4747 m/s) = 7^14 .12 x 10m/s
(c) Find Centripetal Acceleration:
a(centripetal) = (V tangential)^2 / (radius) = (7.12 x 10^14 m/s)^2 / (1.5 x 10^11 m) = 3.38 x 10^18 m/s^2
Please check my work and point out a quick way to fix something. I know this can be easy for any physics expert, but I am just a beginner-so help me in simple terms
My Approach:
(a) Finding Velocity:
V = (1.5 x 10^11 m)/(3.16 x 10^7 s) = 4747 m/s
--I did this because I'm assuming the Earth's orbit of the sun is constant
(b) Tangential Speed:
V = rw = (1.5 x 10^11 m) (4747 m/s) = 7^14 .12 x 10m/s
(c) Find Centripetal Acceleration:
a(centripetal) = (V tangential)^2 / (radius) = (7.12 x 10^14 m/s)^2 / (1.5 x 10^11 m) = 3.38 x 10^18 m/s^2
Please check my work and point out a quick way to fix something. I know this can be easy for any physics expert, but I am just a beginner-so help me in simple terms