Consider the rear view of a bus turning right. If the driver turned the bus while travelling too fast, the bus could topple over. If the bus did topple would the bus fall to the left or to the right?
Since the bus was turning to the right, the centripetal force is to the right. centripetal force =mv^2/r so if it is too fast, velocity would increase and centripetal force would increase and the bus would topple to the right. However, the answer to this question says:
•The bus would tip to the left.
• The force of friction between the tyres and the road provides the
centripetal force at the base of the bus, providing an unbalanced
moment about the bus’s centre of mass 
• causing it to topple anticlockwise. 
Can someone please explain this to me?
Fc = (mv^2)/r
The Attempt at a Solution
please see above