Centripetal Force Theory Questions

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SUMMARY

The discussion focuses on the principles of centripetal force and its implications in various scenarios involving circular motion. Key points include the understanding that a projectile in free fall experiences zero apparent weight, and that the tension in a string at the highest point of a vertical circular motion is less than the weight of the object if the speed is at the minimum required for circular motion. Additionally, the radial acceleration varies depending on the distance from the center of rotation, confirming that not all points on a rotating wheel have the same radial acceleration.

PREREQUISITES
  • Understanding of centripetal force and its calculation (Fc = Ft + Fg)
  • Knowledge of circular motion dynamics and tension in strings
  • Familiarity with free body diagrams and force analysis
  • Concept of radial and tangential acceleration in circular motion
NEXT STEPS
  • Study the derivation and applications of centripetal force equations
  • Learn about the relationship between speed and tension in vertical circular motion
  • Explore the effects of varying radius on radial acceleration in rotating systems
  • Investigate the principles of angular momentum and its conservation in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to centripetal force and dynamics in circular paths.

DanielleG
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Homework Statement




  1. Answer True, False, or Cannot tell to each of the five statements below.
    1. A small projectile is launched horizontally 1 m above the surface of a smooth, airless planet, with sufficient speed for orbit. A bug riding in a small hole in the projectile has apparent weight equal to zero.
    2. A ball on a string moves in a vertical circle. When the ball is at its highest point, the tension in the string is less than the ball's weight.
    3. The figure shows the radial acceleration ar at four sequential points on the trajectory of a particle moving in a circle. The tangential acceleration at point 3 points up.
      circle2.gif
    4. All points on a rotating wheel have the same radial acceleration.
    5. A marble rolls around the inside of a cone. For the marble at the right side of the cone, the free body diagram is correct.
      marblecone.jpg
      fbd2.gif

Homework Equations



Not many equations for this, just theory

The Attempt at a Solution


1) True! Apparent weight = 0 N in free fall.
2) Unsure, but am leaning towards false.
3) Cannot tell! Depends on which way the particle is moving.
4) False, depends on the way the wheel is rotating.
5) False, Fc should be pointing to the left, not the right.

I have only one try left, and I'm just very unsure about b on the most part. Any guidance concerning #2? Thanks in advance!
 
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For number two think what is actually happening when the ball is at the highest point. Draw a force diagram for the ball at the highest point and note what force is holding the ball down and what is holding it up (tension).
 
For 3 and 4 you have the right answer but the reason you offer is wrong.
For 5, is it clear what the c in Fc stands for?
 
RaulTheUCSCSlug said:
Draw a force diagram for the ball at the highest point and note what force is holding the ball down and what is holding it up (tension).

I've drawn a diagram and I know that at the top both the weight and tension are pointing down, but I am unsure of how to know which is smaller or larger.
 
haruspex said:
For 3 and 4 you have the right answer but the reason you offer is wrong.

Hmmmm, okay, I'll give it some thought.

haruspex said:
For 5, is it clear what the c in Fc stands for?

I am basically positive it stands for centripetal force.
 
DanielleG said:
I've drawn a diagram and I know that at the top both the weight and tension are pointing down,

Correct!

The sum of those two forces equals ...
 
Mister T said:
The sum of those two forces equals ...

The centripetal force! So Fc = Ft + Fg, which can be rearranged to give Ft = Fc - Fg. Does that mean the tension in the string is greater than the ball's weight?
 
DanielleG said:
The centripetal force! So Fc = Ft + Fg,

Correct!

which can be rearranged to give Ft = Fc - Fg.

I don't see how that rearrangement helps determine if Ft is less than Fg.

Does that mean the tension in the string is greater than the ball's weight?

Think about the ball's speed if Ft = 0. This is the minimum speed needed to maintain circular motion, a question sometimes asked on tests!
 
Last edited:
Mister T said:
Think about the ball's speed if Ft = 0. This is the minimum speed needed to maintain circular motion, a question asked on test questions!

So the minimum speed needed to keep a ball in circular motion occurs when Ft = 0. Does that mean the weight is what's keeping the ball going in a circular motion? And if that's the case, then the tension in the string is definitely less than the ball's weight.
 
  • #10
DanielleG said:
So the minimum speed needed to keep a ball in circular motion occurs when Ft = 0. Does that mean the weight is what's keeping the ball going in a circular motion?

When the ball is at that position, yes.

And if that's the case, then the tension in the string is definitely less than the ball's weight.

And if the speed is larger than that minimum value Ft will be larger. Anything happen if Ft is larger yet and equal to Fg? Larger than that? What can you say about the ball's speed in each of these cases?

Thinking about these things now will definitely help you later when you're taking a test.
 
Last edited:
  • #11
Mister T said:
Anything happen if Ft is larger yet and equal to Fg? Larger than that? What can you say about the ball's speed in each of these cases?

Hmmm, would v get larger as Ft becomes larger?
 
  • #12
DanielleG said:
Hmmm, would v get larger as Ft becomes larger?

You got it!
 
  • #13
DanielleG said:
The problem statement
The figure shows the radial acceleration ar at four sequential points on the trajectory of a particle moving in a circle. The tangential acceleration at point 3 points up.

circle2.gif



The attempt at a solution

Cannot tell! Depends on which way the particle is moving.

Suppose the particle is moving in the clockwise direction. If the tangential component of the acceleration points upward the particle is speeding up. If downward the particle is slowing down.

If the particle is moving in the counter-clockwise direction we would have the opposite situation.

In general, if the directions of the velocity and the tangential component of the acceleration are the same, the particle is speeding up.

If the directions of the velocity and the tangential component of the acceleration are opposite, the particle is slowing down.
 
  • #14
DanielleG said:
The problem statement
All points on a rotating wheel have the same radial acceleration.

The attempt at a solution
False, depends on the way the wheel is rotating.

Points on the wheel that are different distances from the center will have different radial accelerations.

a
c = v2/r.
 
  • #15
Mister T said:
You got it!
Thank you!
 

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