Centripital F. : Solve for Velocity given ax and r

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SUMMARY

The discussion focuses on calculating the speed of an orbiter in a circular orbit just above a planet's surface, where the gravitational acceleration is 1.88 m/s² and the planet's radius is 1.33 x 106 m. The key equation used is a = v²/r, which relates acceleration, velocity, and radius. The initial calculation yielded a speed of 1547.255 m/s, but a rounding error in the gravitational acceleration was identified as the source of confusion. The correct calculation should use the exact value of 1.88 m/s² for accurate results.

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Homework Statement


Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 1.88 m/s2. The radius of the planet is 1.33 x106 m.


Homework Equations


a=v2/r


The Attempt at a Solution



I have done : √(1,330,000 m * 1.8 m/s2)

with a result of 1547.255 m/s. I'm not sure what part I'm not comprehending -- thank you in advance for any light you can shed on this!
 
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subzero800 said:
I have done : √(1,330,000 m * 1.8 m/s2)

with a result of 1547.255 m/s. I'm not sure what part I'm not comprehending -- thank you in advance for any light you can shed on this!
Except for rounding off 1.88 m/s^2 to 1.8 for some reason, your work looks fine. Redo that calculation.
 
That was it, Thanks Doc!
 

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