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Centripital F. : Solve for Velocity given ax and r

  1. May 30, 2012 #1
    1. The problem statement, all variables and given/known data
    Find the speed of an orbiter in a circular orbit that is just above the surface of a planet, given that the orbiter's acceleration is equal to the planet's gravitational acceleration of 1.88 m/s2. The radius of the planet is 1.33 x106 m.


    2. Relevant equations
    a=v2/r


    3. The attempt at a solution

    I have done : √(1,330,000 m * 1.8 m/s2)

    with a result of 1547.255 m/s. I'm not sure what part I'm not comprehending -- thank you in advance for any light you can shed on this!
     
  2. jcsd
  3. May 30, 2012 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Except for rounding off 1.88 m/s^2 to 1.8 for some reason, your work looks fine. Redo that calculation.
     
  4. May 30, 2012 #3
    That was it, Thanks Doc!
     
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