Characteristic Function of a Compound Poisson Process

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SUMMARY

The characteristic function (CF) of a Compound Poisson Process (CPP) is derived using the formula CF(X) = E[exp{i*u*X}], where X(t) = Σ from j=1 to Nt {Yj}, with Yj being independent and normally distributed. The process involves calculating E[(CFy(u))^N] and recognizing that this can be expressed as a moment generating function, specifically Phi_N(ln[CFy(u)]). To evaluate expressions of the form E[z^N], one can utilize the Poisson distribution with P[N=n] = exp(-L*t)*(L*t)^n/n!, where L represents the rate of the Poisson process.

PREREQUISITES
  • Understanding of Compound Poisson Processes (CPP)
  • Familiarity with characteristic functions (CF)
  • Knowledge of moment generating functions (MGF)
  • Basic principles of Poisson distribution
NEXT STEPS
  • Study the derivation of characteristic functions for Compound Poisson Processes
  • Explore the properties of moment generating functions in probability theory
  • Learn about the applications of Poisson processes in stochastic modeling
  • Investigate the relationship between normal distributions and Poisson processes
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Mathematicians, statisticians, and data scientists interested in stochastic processes, particularly those working with Compound Poisson Processes and their applications in modeling random phenomena.

mikhairu
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Hello,

I am trying to find a characteristic function (CF) of a Compound Poisson Process (CPP) and I am stuck :(.

I have a CPP defined as X(t) = SIGMA[from j=1 to Nt]{Yj}. Yj's are independent and are Normally distributed.

So, in trying to find the CF of X I do the following:
(Notation: CFy = Characteristic Function of y (y is subscript))

CF(X) = E[exp{i*u*X}]
= E[ (E[exp{i*u*Y}])^N ]
= E[ (CFy(u))^N ]
= E[ (exp{ ln[CFy(u)] })^N ]
which is really just a moment generating function Phi_N (Phi subscript N):
Phi_N( ln[CFy(u)] ).

I don't know how to go from here... Y's are Normally distributed but the entire process is Poisson.. so I'm not sure how to combine these. Please help!

Thank you.
 
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mikhairu said:
Hello,

I am trying to find a characteristic function (CF) of a Compound Poisson Process (CPP) and I am stuck :(.

I have a CPP defined as X(t) = SIGMA[from j=1 to Nt]{Yj}. Yj's are independent and are Normally distributed.

So, in trying to find the CF of X I do the following:
(Notation: CFy = Characteristic Function of y (y is subscript))

CF(X) = E[exp{i*u*X}]
= E[ (E[exp{i*u*Y}])^N ]
= E[ (CFy(u))^N ]
= E[ (exp{ ln[CFy(u)] })^N ]
which is really just a moment generating function Phi_N (Phi subscript N):
Phi_N( ln[CFy(u)] ).

I don't know how to go from here... Y's are Normally distributed but the entire process is Poisson.. so I'm not sure how to combine these. Please help!

Thank you.

After line 3 it should be possible to evaluate expressions of the form E[z^N] using P[N=n]=exp(-L*t)*(L*t)^n/n! where L is the rate of the Poisson process.
 

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