Understanding Conventional Current and Electron Flow

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Conventional Current?

Hi guys,

I have a pretty simple conceptual problem that has been bugging me for a while. In a D.C. circuit, the conventional current moves from higher potential to lower potential. But the electron flow is opposite that of the conventional current. That means that the electrons move from lower potential to higher potential?? How can that be possible, since the heat loss in the wires should arise in electron flow from higher to lower potential.
 
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When a charge moves from potential V1 to V2, work done = q(V2-V1). This work done is manifested as heat loss. Since q for an electron is negative, V2-V1 is also negative to make work done positive, => v2<V1.
 
ohhhhhhhhhhhhhh so you can consider charges with the polarity in the electrostatic equations! Well, i guess my teacher was too lazy and taught the topic using modulus.