Choose the element in each of the sets you would expect to have the highest IE2

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SUMMARY

The element with the highest second ionization energy (IE2) among the given options is potassium (K). This conclusion is based on the periodic trends where ionization energy increases across a period and decreases down a group. After the first ionization, potassium achieves the electron configuration of argon, resulting in increased stability and a higher IE2. In contrast, elements like beryllium (Be), magnesium (Mg), calcium (Ca), and aluminum (Al) have outer shell electron configurations that allow for easier ionization, leading to lower IE2 values.

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  • Understanding of periodic table trends
  • Knowledge of ionization energy concepts
  • Familiarity with electron configurations
  • Basic chemistry principles regarding stability of elements
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  • Research exceptions to general trends in ionization energy
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CMATT
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Homework Statement


Choose the element in each of the sets you would expect to have the highest IE2.

a. K
b. Be
c. Mg
d. Ca
e. Al

Homework Equations


The correct answer is K

The Attempt at a Solution


I do not understand why it is K ...I kind of guessed by using my Ionization Energy diagram that shows the trend on the periodic table as:

--------> IE increases across a period/row
|
|
|
IE decreases down a group

Can someone please explain why K is correct?
 
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What do you know about number of valence electrons in elements? How does it depend on the the element position in the periodic table? Why do the valence electrons are valence electrons?
 
That's a general trend.But there are exceptions. Besides you have to compare IE2.So this can't be used.
After 1st Ionisation K attains the EC of nearest noble gas i.e. Argon which means it is highly stable.So IE2 of K is highest.
On the other hand if you see Be,Mg,Ca then the outer shell EC of these elements after 1st ionisation is ns1.So they can easily ionise to gain stability.

CMATT said:

Homework Statement


Choose the element in each of the sets you would expect to have the highest IE2.

a. K
b. Be
c. Mg
d. Ca
e. Al

Homework Equations


The correct answer is K

The Attempt at a Solution


I do not understand why it is K ...I kind of guessed by using my Ionization Energy diagram that shows the trend on the periodic table as:

--------> IE increases across a period/row
|
|
|
IE decreases down a group

Can someone please explain why K is correct?
 

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