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## Homework Statement

A circular curve of highway is designed for traffic moving at 95 km/h. Assume the traffic consists of cars without negative lift. (a) If the radius of the curve is 110 m, what is the correct angle of banking of the road?

## Homework Equations

F_y = N sin(theta) = (mv^2)/r

F_x = N cos(theta) = mg

## The Attempt at a Solution

I assumed that if N = mg then I could cancel out m from either equation since I don't know it initially.

Then I would be left with:

sin(theta) = ((mv^2)/r)/N

cos(theta) = (mg)/N

I used my sin equation. With v = 26.38 m/s and r = 110 m and g = 9.8 m/s^2

I ended up with: sin(theta) = .64589 which is the coefficient of friction.

Doing the inverse sin of that equation, I got an angle of 40.23 degrees.

It was incorrect. What am I doing wrong?