Circular Motion and maximum speed Problem

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SUMMARY

The discussion focuses on calculating the maximum speed, centripetal acceleration, and angular momentum of a 1200 kg convertible negotiating a flat curve with a radius of 45 meters and a coefficient of static friction (μs) of 0.50. The maximum speed is determined using the formula v = sqrt(r * g * μs), resulting in a maximum speed of 2.37 m/s. The centripetal acceleration at this speed is calculated as 0.124 m/s². The discussion highlights the importance of correctly interpreting the coefficient of static friction as dimensionless.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with centripetal force equations
  • Knowledge of angular momentum concepts
  • Basic physics of friction and motion
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  • Research the derivation of centripetal force equations
  • Learn about angular momentum calculations in rotational motion
  • Explore the effects of varying coefficients of friction on vehicle dynamics
  • Study real-world applications of circular motion in automotive engineering
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thanlong01
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The problem is like this: It's a beautiful spring day so you decide to take a cruise in your fancy new 1200 kg convertible. While driving, you notice a sign that says "Warning! Flat level curve with radius 45m. Coefficient of static friction for all tires us = 0.50'' With your knowledge of physics:
a) What is the maximum speed that you can safely negotiate the curve (without sliding)?

b) what is your centripetal acceleration at this speed around the curve?

c) What is the angular momentum of your car doing the speed limit around this curve?


The equation sheet is attached.


I tried to solve the problem but i m not sure it's right or not.

Here is my attempt:
a)
Ffriction = m v^2 r
r u m g = m v^2
v = sqrt (r u g)
v = sqrt (45 * 9.8 * 0.0127) //0.0127 -> I converted u from "in" to "meter"
v = 2.37m

b) a = v^2 / r
a = (2.37)^2 / 45 = 0.124 m/s^2

and that what i get so far.. i don't know how to do C
 

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thanlong01 said:
Here is my attempt:
a)
Ffriction = m v^2 r
r u m g = m v^2
v = sqrt (r u g)
v = sqrt (45 * 9.8 * 0.0127) //0.0127 -> I converted u from "in" to "meter"
v = 2.37m
μs is a dimensionless coefficient. It has no units. In this problem, μs = 0.50, not 0.50 inches.
 

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