Circular motion- finding angle of the banking

Click For Summary
SUMMARY

The discussion centers on calculating the angle of banking for a circular highway curve designed for vehicles traveling at 60 km/h with a radius of 200 m. The user initially applies the formula θ = tan-1(v2/rg) but encounters an unrealistic angle of nearly 90 degrees. The primary error identified is the use of inconsistent units, specifically the need to convert speed from kilometers per hour to meters per second for accurate calculations. Correcting the units will yield a more reasonable angle of banking.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with trigonometric functions and their applications
  • Knowledge of unit conversions, particularly speed and distance
  • Basic physics concepts related to friction and forces
NEXT STEPS
  • Learn about unit conversions for speed from km/h to m/s
  • Study the derivation and application of the banking angle formula in circular motion
  • Explore the concept of the coefficient of friction in relation to circular motion
  • Investigate the effects of different speeds on banking angles and friction requirements
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in automotive engineering or road design, particularly those interested in the dynamics of vehicle motion on curved paths.

wxwolf
Messages
1
Reaction score
0

Homework Statement


A banked circular highway curve is designed for traffic moving at 60km/h the radius of the curve is 200m traffic is moving along the highway at 40km/h on a rainy day. what is the minimum coefficient of friction between the tires and the road that will allow cars to take the turn without sliding off the road (assume the cars do not have negative lift)


Im trying to find the angle of the banking first. i used [theta=tangent^-1(v^2/rg)] where r is the radius, v is the velocity and g is gravity.

when i do the problem out though:

=tan^-1(60km/h)^2/(.2km)(9.8m/s^2)
=tan^-1(3600)/(1.96)
=tan^-1(1836.73)
=89.96

there is no way that banking is almost 90 degrees. Where am i going wrong?

once i do that, I can plug it in and solve the problem for the kinetic coefficient.
 
Physics news on Phys.org
You're messing up with units. Use standard units for speed (m/s) and distance (m).
 

Similar threads

Replies
9
Views
3K
Replies
6
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K