Circular Motion: Max Revolutions per Second w/ 9g Accel.

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The discussion focuses on calculating the maximum revolutions per second for a spaceman undergoing circular motion with a radius of 5 meters and an acceleration limit of 9g. The relevant formulas for centripetal acceleration are provided: a = mv²/r and a = mr²ω. Given that the acceleration due to gravity (g) is approximated as 10 m/s², participants are encouraged to apply these equations to derive the maximum permissible revolutions.

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  • Centripetal acceleration concepts
  • Understanding of angular velocity (ω)
  • Basic physics of rotational motion
  • Familiarity with the formula a = mv²/r
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Circular Motion

A spaceman is in training is rotated in a seat at the end of a horizontal rotating are of length 5m. If he can withstand accelerations up to 9g, what is the maximum number of revelutions per second permissable? The acceleration of free fall (g) may be taken as 10m/s.

i would give what i have tried but i have no idea what equation to use?
any ideas?
 
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Hi ben2010! :wink:

Use the formula for centripetal acceleration …

a = mv2/r = mr2ω :smile:
 

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