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Homework Statement
The distance between the both nucleons in the H2 molecule is 0.0741 nm
The energy for the 3 lowest radiation levels of the molecule are:
##E_{0}=0 \\
E_{1}=0.0151 eV \\
E_{2}=0.0453 eV##
How many revolutions per second does the molecule rotate with in the different states?
Homework Equations
See attachment
The Attempt at a Solution
How many revolutions per second does the molecule rotate with? I thought that if f in the last equation above is frequency then the rotational speed would be omega=f*2pi. So if we rewrite the last equation we get
## f=\frac{E_{v}}{(\nu+1/2)h} \Leftrightarrow \omega=\frac{2\pi* E_{v}}{(\nu+1/2)h} ##
Of course the first level gives zero rev/s but for the others I get the wrong answer. When putting in the above values, I get
##\omega=\frac{2\pi* 0.0151* 1.606*10^{-19}}{(1+1/2)*6.626*10^{-34}}=1.53*10^{14} rev/s ## which is incorrect. Also the other value gives the wrong answer in this equation.
The correct answers should be:
##\omega_0 = 0 \\ \omega_1 = 5.2*10^{12} \\ \omega_2 = 9.0*10^{12} \\ (rev/s)##
I don't understand how to get to these answers. Shouldn't the above equation be used? Or is it something else that needs to be taken into consideration? Please help how to get to these answers.
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