Circular motion. Uniform and accelerating. (Bridge)

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Homework Help Overview

The discussion revolves around a problem involving circular motion, specifically analyzing the motion of a bridge that opens from 0 to 80 degrees over a period of 2 minutes. The first 20 degrees involve acceleration, while the last 60 degrees are at a constant angular velocity. Participants are exploring how to determine the acceleration for the initial segment and the angular velocity for the latter segment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up equations to solve for acceleration and angular velocity but expresses uncertainty about the reasoning behind the chosen equations. Other participants question the justification for using specific equations and the order in which they are applied. There is a focus on understanding the underlying principles of constant acceleration equations.

Discussion Status

Participants are actively engaging in clarifying the reasoning behind the equations used and discussing their relationships. Some guidance has been offered regarding the nature of the equations and their applicability, but there is no explicit consensus on the best approach or understanding of the problem.

Contextual Notes

There is a noted lack of understanding regarding the derivation and selection of the equations used in the problem-solving process. Participants are also grappling with the implications of the variables involved, particularly the need for angular velocity in certain equations.

EVriderDK
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Homework Statement



A bridge takes 2 minutes to open up fully from 0 to 80 degrees. The first 20 degrees it is accelerating, and the last 60 degrees it is traveling with even velocity.

I will have to find acceleration for the first 20 degrees and angular velocity for the last 60 degrees.

http://peecee.dk/upload/view/357409 Illustration.

The Attempt at a Solution



I have tried setting up three equations with three unknowns:

http://peecee.dk/upload/view/357410

I have tried isolating a in the first two equations, and then put 1=2. Then isolating ω in this new equation, and replacing this with the ω in the third equation. Then i isolate t, and get 48 second. This gives the correct answer to the acelleration, but i don't know why. Can you help?

Is there other way to do it maybe?

Thank you in advance.
 
Last edited:
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Hi EVriderDK! :smile:

That looks ok … you eliminated α, then you solved for t, that is the way to do it.
EVriderDK said:
…This gives the correct answer to the acelleration, but i don't know why.

I don't understand. If it solves the equations, isn't that enough justification? :confused:
 
Why is it correct to use these three equations. I didn't come up with them my self.
I was just told that this i s the correct way to do it, but i lack the understanding.
 
EVriderDK said:
… I didn't come up with them my self.

ah! :rolleyes:

ok, first, are you familiar with the standard constant acceleration equations for ordinary (linear) motion?
 
Yes I'm familiar with all the formulas, i just cannot see, how the person who put them together, knew, that this was the way to do it.
 
if a is constant …

then dv/dt = a, so ∆v = at

d2x/dt2 = a, so ∆x = vot + 1/2 at2

a = dv/dt = dv/dx dx/dt = vdv/dx = 1/2 d(v2)/dx, so ∆(v2) = 2as :wink:
 
But how did he know, that I had to use these three equations, in that order etc. ?
 
Argh! :D

Let me rephrase.

How to find out how many equations you are going to work with, and what these equations have to contain?
 
  • #10
it's always obvious which one to use …

it's the one that has the variables you're given, and the variable you want

one has s u a and t

one has u v a and s

one has u v a and t​
 
  • #11
So because i don't have ω in the first equation, i have to have an equation with ω in it? Because the third equation needs this ω ?
 

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