Classifying Symmetric Quadratic Forms

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SUMMARY

This discussion focuses on classifying symmetric bilinear forms on R^3 using matrix representation and diagonalization techniques. The participant proposes utilizing the standard basis for R^3 and the symmetric matrix M in the form x^T.M.y. The conclusion is that all symmetric bilinear forms can be represented as diagonal matrices, factoring out equivalences through linear isomorphisms. Additionally, it is noted that diagonal matrices can be simplified to have entries of 1, -1, or 0, with zero entries indicating non-degenerate forms, a concept derived from Gram-Schmidt orthogonalization.

PREREQUISITES
  • Understanding of symmetric bilinear forms
  • Familiarity with matrix diagonalization
  • Knowledge of linear isomorphisms
  • Concepts of Gram-Schmidt orthogonalization
NEXT STEPS
  • Study the properties of symmetric bilinear forms in linear algebra
  • Learn about matrix diagonalization techniques in detail
  • Explore linear isomorphisms and their applications in vector spaces
  • Investigate the Gram-Schmidt process and its implications for orthogonalization
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Mathematicians, students of linear algebra, and anyone interested in the classification and properties of symmetric bilinear forms in vector spaces.

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Hi, All:

I am trying to see how to classify all symmetric bilinear forms B on R^3 as a V.Space
over the reals.

My idea is to use the standard basis for R^3 , then use the matrix representation M
=x^T.M.y . Then, since M is, by assumption, symmetric, we can diagonalize M.

So it seems all symmetric bilinear forms are just all diagonal matrices; maybe we
need to factor out those that are equivalent as bilinear forms, i.e., B,B' are equivalent
if there is a linear isomorphism L:R^3-->R^3 with B(v)=B'(L(v)).

Is this right? Is there anything else?
 
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You can even do better! You can even diagonalize those forms such that the diagonal matrix only has 1, -1 or 0 as diagonal entries!
A symmetric bilinear form with 0 as diagonal entry are exactly the non-degenerate forms.

All this actually follows from Gram-Schmidt orthogonalization.

See http://mathworld.wolfram.com/SymmetricBilinearForm.html
 

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