Closed-Form Solution for f(n) w/o Generating Fns

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Homework Help Overview

The discussion revolves around finding a closed-form solution for the recursive function f(n), defined piecewise for n ≤ 2 and n > 2, where f(n) involves a square root and a recurrence relation. The original poster expresses frustration with generating functions and recursive attempts, while also questioning the possibility of establishing an asymptotic bound without a closed form.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the feasibility of obtaining a closed form for f(n) and discuss the potential for asymptotic analysis. Some suggest that a closed form may not be possible, while others propose specific forms for f(n) based on ranges of n.

Discussion Status

The conversation includes varying opinions on the possibility of a closed-form solution, with some participants expressing skepticism. A specific form for f(n) has been proposed, but there is no consensus on its validity or derivation, and the original poster's frustration indicates ongoing uncertainty.

Contextual Notes

The original poster mentions limitations in their mathematical presentation skills and expresses dissatisfaction with their progress, which may affect the clarity of the discussion.

Tony11235
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[tex]f(n) = 0, n \leq 2[/tex]

[tex]f(n) = \sqrt{n}f(\sqrt{n}) + n, n > 2[/tex]

How can I get this in closed form? Generating functions won't work. Recuring a number of times hasn't worked out for me. Or can I show that f = O(n*lg(lg(n))), where lg stands for ln(n)/ln(2), without f being in closed form? Sorry for the poor tex skills.
 
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I don't think it can be put in closed form.

Daniel.
 
f(n)= kn for [itex]2^{k}< n \le 2^{k+1}[/itex]
 
HallsofIvy said:
f(n)= kn for [itex]2^{k}< n \le 2^{k+1}[/itex]

Are you serious? This is the closed form I've been struggling all day to find? Could you mention how you arrived at this? Sorry it's not totally obvious to me, I'm really tired.
 
Nevermind. No explanation needed. I'm just really pissed with myself.
 

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