Calculate Combinations of 10 Items (Max 3) - Paul

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SUMMARY

The discussion focuses on calculating the number of combinations for creating a sandwich with specific constraints. Given 10 items, including 3 types of bread, 3 types of meat, 4 types of cheese, and 8 toppings, the user can select one bread, one meat, up to two cheeses, and up to three toppings. The total number of combinations is derived using the combination formula P(n,r)=n!/(n-r)!, leading to a calculated total of 120 combinations for the cheese selection alone. The discussion emphasizes the importance of using combinations rather than permutations due to the non-importance of order in sandwich toppings.

PREREQUISITES
  • Understanding of combinations and permutations
  • Familiarity with the combination formula P(n,r)=n!/(n-r)!
  • Basic knowledge of the fundamental principle of counting
  • Concept of the rule of product in combinatorial mathematics
NEXT STEPS
  • Research the application of the combination formula in real-world scenarios
  • Learn about the fundamental principle of counting in combinatorial problems
  • Explore advanced combinatorial techniques, such as generating functions
  • Study the differences between permutations and combinations in depth
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This discussion is beneficial for students, educators, and professionals in mathematics, particularly those interested in combinatorial analysis and its applications in problem-solving scenarios.

paulhunn
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Say i needed to calculate the different number of combinations there are if you have 10 items and can pick up to 3 of them. e.g you buy a sandwhich and have Ketchup, Mustard, Relish, Lettuce, Pickles, Sour Cream, Cream Cheese, Olives as available toppings but you can only choose up to three. how many combinations are there?

Thanks
Paul
 
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What have you done so far to solve your problem?
 
Well the entire problem is as follows:
You are at a corner deli with a craving for a sandwich, here's the menu:
Breads: wheat, rye, white
Meats: turkey, ham, salami
Cheeses: American, Swiss, Cheddar, Gouda
Toppings: Ketchup, Mustard, Relish, Lettuce, Pickles, Sour Cream, Cream Cheese, Olives

You can only get one kind of bread (you have to have bread, no low-carb diet).
Per sandwich you're only allowed up to one kind of meat, up to two kinds of cheese, and up to three toppings. This means you can have none of the above options. The minimum required food is bread with nothing on it.

How many different options do you have?



So far i have worked out that there are 120 combinations up to the cheese selection (unless i have made an error)
 
Use combination and fundamental principle of counting
 
think of how many choices you have for the each selection. Then you can use the rule of product or the formula P(n,r)=n!/(n-r)! might help you out.
 
buzzmath said:
think of how many choices you have for the each selection. Then you can use the rule of product or the formula P(n,r)=n!/(n-r)! might help you out.

I don't think this would be a situation to use a permutation, a combination would be better, i think the problem would consider a sandwich with lettuce and chese to be the same as a sandwich with cheese and lettuce, so order doesn't matter. Don't read too much into that example because it doesn't really fit what the problem is asking but it gets my point across..
 
Solve in three cases. In each case you can use combination and further you can add the three cases to get the result.
 

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