Combination/probability question (High School level)

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Discussion Overview

The discussion revolves around a counting and probability problem, specifically focusing on how to correctly calculate combinations of students based on gender for a hypothetical scenario. Participants explore different methods for approaching the problem and clarify misunderstandings related to counting techniques.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant describes their initial approach to the problem and expresses confusion about why it yields an incorrect answer.
  • Another participant points out that the initial method results in overcounting groups with 3 girls.
  • A participant suggests that treating each situation separately (e.g., calculating combinations for 2 girls and 1 boy, then for 3 girls and 0 boys) is a better strategy.
  • There is a comment questioning the randomness of selecting students for a debate, which introduces a humorous perspective on the scenario.

Areas of Agreement / Disagreement

Participants generally agree that separating cases can help avoid overcounting, but there is no consensus on a single "best" approach due to the variety of problems that exist. Additionally, the humorous exchange about the randomness of selection indicates differing views on the context of the problem.

Contextual Notes

The discussion does not resolve the mathematical steps involved in the counting problem, and assumptions about the context of student selection remain unexamined.

Micky1964
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Hi all. I'm doing a counting/probability problem here.
I can see how the correct answer for part b is arrived at by counting the number of combinations for "2 girls" then counting the number of combinations for "3 girls" , and adding these results.
But I've attached my first way of approaching it, which is wrong. Wondering if anyone can tell me why my approach doesn't give the correct answer. I know it's probably something obvious that I'm missing.
Thanks
 

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With your method groups with 3 girls get counted 3 times each rather than once each.
 
romsek said:
With your method groups with 3 girls get counted 3 times each rather than once each.
Thank you for replying. I can see that makes sense now.

So the best approach with these types of problems is to treat each situation separately? ie. find how many ways you can have 2 girls and 1 boy, then find how many ways you can have 3 girls and 0 boys, then add the 2 figures?

Mick
 
Micky1964 said:
Thank you for replying. I can see that makes sense now.

So the best approach with these types of problems is to treat each situation separately? ie. find how many ways you can have 2 girls and 1 boy, then find how many ways you can have 3 girls and 0 boys, then add the 2 figures?

Mick

It's a bit difficult to cite any approach as "best" given the variety of problems that exist but generally separating the cases helps ensure you won't multiply count specific situations.
 
I think it odd that choosing students "to represent the class in a debate" would be done at random!
 
Country Boy said:
I think it odd that choosing students "to represent the class in a debate" would be done at random!
You clearly never went to my High School.

-Dan
 
Yeah, I dropped out in the fourth grade!
 

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