Combination Problem: C(70,67) = 54,740

  • Context: MHB 
  • Thread starter Thread starter yakin
  • Start date Start date
  • Tags Tags
    Combination
Click For Summary
SUMMARY

The combination C(70,67) equals 54,740, calculated using the formula C(n,r) = n! / (r!(n-r)!). Specifically, C(70,67) simplifies to C(70,3) due to the property C(n,r) = C(n,n-r). The calculation proceeds as follows: C(70,3) = (70 * 69 * 68) / (3 * 2 * 1), resulting in 54,740. This confirms the mathematical validity of the combination function in combinatorial mathematics.

PREREQUISITES
  • Understanding of factorial notation and operations
  • Familiarity with combinatorial mathematics
  • Knowledge of the properties of combinations
  • Basic algebra for simplifying expressions
NEXT STEPS
  • Study the properties of combinations and permutations in depth
  • Learn about Pascal's Triangle and its relation to combinations
  • Explore applications of combinations in probability theory
  • Investigate advanced combinatorial identities and their proofs
USEFUL FOR

Mathematicians, students studying combinatorics, educators teaching probability and statistics, and anyone interested in mathematical problem-solving techniques.

yakin
Messages
42
Reaction score
0
How come the combination of C(70,67) is 54,740?
 
Physics news on Phys.org
yakin said:
How come the combination of C(70,67) is 54,740?

The combination function is defined as:

$$C(n,r)={n \choose r}\equiv\frac{n!}{r!(n-r)!}$$

And so we have:

$${70 \choose 67}=\frac{70!}{67!(70-67)!}=\frac{70\cdot69\cdot68\cdot67!}{67!\cdot3!}=\frac{70\cdot69\cdot68}{3\cdot2}=35\cdot23\cdot68=54740$$
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
744
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K