Combinatorics: 16 People Seated in a Row/Circle

  • Context: Undergrad 
  • Thread starter Thread starter Finsfan342
  • Start date Start date
  • Tags Tags
    Combinatorics
Click For Summary
SUMMARY

The discussion focuses on combinatorial seating arrangements for 16 people under specific conditions. For scenario A, the formula is 16! - 13!4! - 14!3! - 15!2!, addressing the restriction of 4 individuals not wanting to sit together. In scenario B, the arrangement of 3 individuals who must sit together is calculated as 14!3! + 15!2!. For circular arrangements in scenario C, the calculation is 12!3! + 13!2!, while scenario D uses the formula 15! - 12!4! - 13!3! - 14!2! to account for 4 individuals not wanting to sit next to each other.

PREREQUISITES
  • Understanding of factorial notation and permutations
  • Familiarity with the Inclusion-Exclusion principle
  • Basic knowledge of combinatorial arrangements in linear and circular formats
  • Experience with mathematical problem-solving techniques
NEXT STEPS
  • Study the Inclusion-Exclusion principle in depth
  • Learn about permutations and combinations in combinatorial mathematics
  • Explore circular permutations and their unique properties
  • Practice solving complex seating arrangement problems
USEFUL FOR

Mathematicians, students studying combinatorics, educators teaching combinatorial principles, and anyone interested in solving seating arrangement puzzles.

Finsfan342
Messages
1
Reaction score
0
In how many ways can 16 people be seated:

A. In a row, if 4 of the 16 do not want to sit next to one another

B. In a row, if 3 of the 16 must be seated next to one another

C. In a circle, if 3 of the 16 must be seated next to one another

D. In a circle, if 4 of the 16 do not want to sit next to one another

These are my answers,

A. 16! - 13!4! - 14!3! - 15!2!, I'm not sure if I should include the 14!3! and 15!2!

B. 14!3! +15!2!, same situation as A

C. 12!3! + 13!2!, Little confused with the circle situation

D. 15! - 12!4! - 13!3! - 14!2!
 
Physics news on Phys.org
Finsfan342 said:
In how many ways can 16 people be seated:

A. In a row, if 4 of the 16 do not want to sit next to one another

B. In a row, if 3 of the 16 must be seated next to one another

C. In a circle, if 3 of the 16 must be seated next to one another

D. In a circle, if 4 of the 16 do not want to sit next to one another

These are my answers,

A. 16! - 13!4! - 14!3! - 15!2!, I'm not sure if I should include the 14!3! and 15!2!

B. 14!3! +15!2!, same situation as A

C. 12!3! + 13!2!, Little confused with the circle situation

D. 15! - 12!4! - 13!3! - 14!2!

B. Wrap the special 3 together with duct tape and consider them to be one object. You then have 14 objects to arrange, which can be done in 14! ways. But the special 3 can be arranged in 3! ways, so there are 14! 3! ways in all.

For A, I would try combining the method of B with Inclusion/Exclusion.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K