Combining High and Low Pass Filters

Click For Summary
To isolate a desired signal at 1 GHz from noise using filters, a combination of high-pass and low-pass filters is effective. The high-pass filter will block frequencies below 800 MHz, while the low-pass filter will block frequencies above 1.2 GHz, allowing the desired frequency to pass through. Concerns about blocking all frequencies when combining filters can be addressed by selecting appropriate cutoff frequencies for each filter. The discussion also touches on the importance of Bode plots for understanding filter behavior and calculating attenuation. Proper component values for R and C are crucial for achieving the desired filtering effect.
waley

Homework Statement


Suppose we have a noisy signal (superposition of many frequencies), but
we are only concerned with a particular part of the signal within the noise at a frequency
f(desired) = 1 GHz. In a sentence or two, explain how you could isolate the desired part
of the signal by using low-pass and high-pass filters. Assuming the noise is far from the desired signal in frequency (≥ ±200 MHz from f(desired)), suggest component values that should achieve this effect.

Homework Equations


cutoff frequency: w = (RC)^-1

The Attempt at a Solution


If I use the high-pass filter, all lower frequencies will be blocked; if I use the low-pass, all higher frequencies will be blocked. If I use a combo of both in the same circuit with the same R,C values, then wouldn't all frequencies be blocked?
 
Physics news on Phys.org
waley said:

Homework Statement


Suppose we have a noisy signal (superposition of many frequencies), but
we are only concerned with a particular part of the signal within the noise at a frequency
f(desired) = 1 GHz. In a sentence or two, explain how you could isolate the desired part
of the signal by using low-pass and high-pass filters. Assuming the noise is far from the desired signal in frequency (≥ ±200 MHz from f(desired)), suggest component values that should achieve this effect.

Homework Equations


cutoff frequency: w = (RC)^-1

The Attempt at a Solution


If I use the high-pass filter, all lower frequencies will be blocked; if I use the low-pass, all higher frequencies will be blocked. If I use a combo of both in the same circuit with the same R,C values, then wouldn't all frequencies be blocked?
Are you familiar with the Bode plots of LPF and HPF circuits? What is the attenuation at that ω value you have listed for a single pole filter? What is the attenuation 200MHz away from that cutoff frequency?
 
berkeman said:
Are you familiar with the Bode plots of LPF and HPF circuits? What is the attenuation at that ω value you have listed for a single pole filter? What is the attenuation 200MHz away from that cutoff frequency?
I'm guessing that the plots look something like: they're constant at first but at a certain frequency the curve drops to zero eventually. I'm not sure how to calculate attenuation - all I can guess is that somehow I have to have two values of R and C to fulfill 1.0x10^9 Hz = (2*pi*R*C)^-?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
1K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K