Comparing A & B in Bernoulli Trials w/ X & P

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SUMMARY

This discussion focuses on comparing two sets of estimates, A and B, against a true probability set P in the context of Bernoulli trials. The challenge arises from the limitation of conducting only a single Bernoulli trial for each event represented by the Bernoulli random variables in set X. The proposed solution involves applying a matched-pairs t-test to evaluate the differences between the averages of sets A and B, allowing for a statistical determination of which estimate is closer to the true probabilities in P.

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slipperypete
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Let X be the set X=\left\{x_1,x_2,...,x_n\right\}, where each x_i is a Bernoulli random variable and P be the set P=\left\{p_1,p_2,...,p_n\right\}, where p_i is the probability that x_i=1. Now, suppose there are two other sets, A=\left\{a_1,a_2,...,a_n\right\} and B=\left\{b_1,b_2,...,b_n\right\}, where a_i,b_i are two different estimates for p_i.

In other words, p is the "true" (unknown) probability that x will occur, and a and b are both attempts to estimate that probability.

I am trying to design an experiment that will determine which set, A or B, is "closer" to P.

If these Bernoulli random variables represented, say, different-sided dice, then an experiment would be pretty straightforward: conduct a Bernoulli process; i.e., repeatedly perform a Bernoulli trial.

However, in my case, each x_i represents a real-world event, and can be simulated only once. A Bernoulli process is impossible, I am limited to a single Bernoulli trial. If X=\left\{x_1,x_2,x_3\right\}, then I don't think there would be a practical way to solve this problem at any level of significance. But n here is actually quite large, so I feel like there should be some test which would allow me to show A>B or A<B or A\neq B or A=B.

Any thoughts?
 
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You can apply a matched-pairs t test to the difference between average(A) and average(B).
 

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