Comparing Powers: A Mental Technique

  • Context: Undergrad 
  • Thread starter Thread starter vin300
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Discussion Overview

The discussion revolves around techniques for comparing two powered terms with different bases, specifically focusing on estimating which term is greater without the use of digital aids or calculators. The context includes mathematical reasoning and exploratory techniques.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • One participant inquires about mental techniques to compare terms like 2^200 and 3^120.
  • Another participant suggests using logarithms to compare the two terms, providing calculations to show that 2^200 is greater than 3^120.
  • A third participant clarifies the use of logarithms and presents an algebraic approach to demonstrate the comparison, ultimately concluding that 2^200 is greater than 3^120 without needing a calculator.
  • A later reply expresses gratitude for the information shared.

Areas of Agreement / Disagreement

Participants generally agree on the use of logarithms as a technique for comparison, but there is no explicit consensus on the method's effectiveness or alternative approaches.

Contextual Notes

The discussion does not address potential limitations of the logarithmic method or assumptions about the numbers being compared.

Who May Find This Useful

Individuals interested in mental math techniques, logarithmic comparisons, or mathematical reasoning may find this discussion beneficial.

vin300
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This is by no means a trick question, I would want to know whether there is any technique to compare two powered terms with different bases, that is if I say I want to compare 2 powered 200 to 3 powered 120 to estimate which of these may be greater without any special or digital aid, how can I do it in my mind?
 
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Take the logarithm of both numbers:

ln(2200) = 200 ln 2 = 138.629436112
ln(3120) = 120 ln 3 = 131.83347464

So 2200 > 3120

EDIT: fixed a math error.
 
Are you talking about exponents?
So like x^n vs y^m?
You could just take the logs, and do some algebra.

Have the ~ symbol be a placeholder for =,<,> symbols

2^{200} \sim 3^{120}
200 log(2) \sim 120 log(3)
\frac{200}{120} \sim \frac{log(3)}{log(2)}
\frac{5}{3} \sim log_2(3)
2^{\frac{5}{3}} \sim 3
2^5 \sim 3^3
32 \sim 27

therefore: ~ is >
so
2^{200} &gt; 3^{120}

No calculator needed.
 
Thanks.
 

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