- #1
Plutonium88
- 174
- 0
Completely factor 32x^5 + 243y^5
okay i used synthetic divison and i referenced a factorign calculator to get the answer
Answer: i used f(x) = (2x)^5 + (3y)^5
then f(-3y/2)= (2x)^5 + (3y)^5 = 0 (factor thereom)
using synthetic divison and factor (-3y/2)
i got.. 32x^4 -48x^3y + 72x^2y^2 -108xy^3 + 162y^4
The answer is (2x+3y)(16x^4 -24x^3y + 36x^2y^2 - 54xy^3 + 81y^4)
i notice that the second piece (16x^4...)
the whole piece is actually half of what i long divided..so my problem is why am i not dividing to get that answer? and how can i put together what i knowÉ
okay i used synthetic divison and i referenced a factorign calculator to get the answer
Answer: i used f(x) = (2x)^5 + (3y)^5
then f(-3y/2)= (2x)^5 + (3y)^5 = 0 (factor thereom)
using synthetic divison and factor (-3y/2)
i got.. 32x^4 -48x^3y + 72x^2y^2 -108xy^3 + 162y^4
The answer is (2x+3y)(16x^4 -24x^3y + 36x^2y^2 - 54xy^3 + 81y^4)
i notice that the second piece (16x^4...)
the whole piece is actually half of what i long divided..so my problem is why am i not dividing to get that answer? and how can i put together what i knowÉ