Complimentary Angles: Understand Why sin(90-theta) = cos theta

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SUMMARY

The discussion clarifies the mathematical identity sin(90° - θ) = cos(θ) by explaining the relationship between complementary angles in a right triangle. When two angles sum to 90 degrees, they are complementary, meaning that the sine of one angle equals the cosine of the other. This is demonstrated using the definitions of sine and cosine in the context of a right triangle, where the opposite and adjacent sides are related to the angles involved.

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Homework Statement


It bascially says when the sum of two angles are 90 deg they are complimentary...
Then it goes on saying
sin(90-theta) = cos theta
and so on...

I understand the concept such as if sin(30) = cos(60)
But the book doesn't explain why it works.. it just says if two compl angles are 90 deg then sin(90-theta) = cos theta, which is not an explanation at all...
can some one help me understand why this is?

Thank you.



Homework Equations





The Attempt at a Solution

 
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Miike012 said:
I understand the concept such as if sin(30) = cos(60)
First of all, you forgot the degree marks. If you write "sin(30) = cos(60)", I'm assuming you meant radian measure. You must write sin (30°) = cos (60°). Secondly, If you "understood" the concept above, then why are you asking it in the first place? Sounds like you really don't understand.

Look at this diagram:
[PLAIN]http://home.comcast.net/~yeongil/images/RtTri.jpg
In a right triangle, the two non right-angles have to be complements of each other.
\sin B = \frac{opp}{hyp} = \frac{b}{c}
and
\cos A = \frac{adj}{hyp} = \frac{b}{c}
so
\sin B = \cos A.
Since B = 90° - A,
\sin (90^{\circ} - A) = \cos A.
 
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