(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two medical field teams set out for a reconnaissance mission and lose one another. The GPS at their original camp shows the location of the first medical team as 43 km away, 15° north of west. The second medical team strayed 32 km away, 33° east of north from base camp.

When the first team uses its emergency GPS to check the position of the second team, what does it give for the second team's (a) distance from them and (b) direction, measured from due east?

2. Relevant equations

Rx = ax + bx

Ry = ay + by

a^{2}+ b^{2}= c^{2}

tan^{-1}= opp/adj

3. The attempt at a solution

ax = cos 15° x 43km

= -41.53km

ay = sin 15° x 43km

= 11.13km

bx = sin 33° x 32km

=17.42

by = cos 33° x 32km

= 26.83

Rx = ax + bx

= -41.53km + 17.42km

= - 24.11km

(or if we take positive direction of x the other way)

= +24.11km

Ry = ay +by

= 11.13km + 26.83km

= 37.96km

Rx^{2}+ Ry^{2}= R_{hypotenuse}

= [tex]\sqrt{}-24.11^{2}+ 37.96^{2}[/tex]

= [tex]\sqrt{}2022.3[/tex]

= 44.97km

tan^{-1}= opp/adj

= 57.6°

both answers were wrong. I cannot see what little mistake I am making

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# Homework Help: Components of a vector - don't know what I am doing wrong

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