Components working at a particular time

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SUMMARY

The expected number of working components in a system with 10 components, where the jth component operates with a probability of 1/j, is calculated using the formula E{n} = H_{10}, where H_{10} represents the 10th harmonic number. The harmonic number is defined as the sum of the reciprocals of the first n natural numbers, specifically H_{10} = 1 + 1/2 + 1/3 + ... + 1/10. This calculation assumes that the operational status of each component is independent.

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oyth94
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Hello .Sorry for all the questions I am asking...but I have another one I would like to seek help for.:

Suppose a system has 10 components and that a particular time the jth component is working with probability 1/j for j= 1,2,...10. How many components do you expect to be working at that particular time?

All I have done so far is calculating the probability for all 10 components and I know that the sum of all possible probabilities is 1.

But how should I solve the question?
 
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oyth94 said:
Hello .Sorry for all the questions I am asking...but I have another one I would like to seek help for.:

Suppose a system has 10 components and that a particular time the jth component is working with probability 1/j for j= 1,2,...10. How many components do you expect to be working at that particular time?

All I have done so far is calculating the probability for all 10 components and I know that the sum of all possible probabilities is 1.

But how should I solve the question?

The expected number of working components is...

$\displaystyle E\{n\} = 1 + \frac{1}{2} + \frac{1}{3} + ... + \frac{1}{10} = H_{10}\ (1)$ Since the status of components are independent r.v. nothing can be said about the sum of their probabilities... Kind regards $\chi$ $\sigma$
 

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