Compound Interest: $50000 Invested for 3 Years at 7.75%

  • Context: MHB 
  • Thread starter Thread starter kaye
  • Start date Start date
  • Tags Tags
    Interest
Click For Summary
SUMMARY

The discussion focuses on calculating the future value of a $50,000 investment over 3 years at an annual interest rate of 7.75%, compounded quarterly. Using the formula $A = A_0 \left(1 + \dfrac{r}{n}\right)^{nt}$, where $A_0$ is the initial balance, $r$ is the annual interest rate, and $n$ is the number of compounding periods per year, the quarterly interest rate is determined to be 1.9375%. After 12 quarters, the total amount available for sports equipment is calculated as $50,000(1.019375)^{12}.

PREREQUISITES
  • Understanding of compound interest calculations
  • Familiarity with the formula for future value of investments
  • Basic knowledge of decimal and percentage conversions
  • Ability to perform exponentiation and multiplication
NEXT STEPS
  • Explore advanced compound interest scenarios using different compounding frequencies
  • Learn about the impact of varying interest rates on investment growth
  • Investigate financial calculators or software for investment projections
  • Study the effects of inflation on real investment returns
USEFUL FOR

Finance students, investment analysts, educators in financial literacy, and anyone interested in understanding the mechanics of compound interest and investment growth.

kaye
Messages
2
Reaction score
0
An alumnus of a local high school donated $50000 to the school. The amount was invested for 3 years at 7.75%, compounded quarterly. The school has agreed to use only the interest earned on the investment to buy sports equipment. How much money will be available for sports equipment at the end of the investments term?
 
Physics news on Phys.org
$A = A_0 \left(1 + \dfrac{r}{n}\right)^{nt}$

$A$ = account balance after $t$ years
$A_0$ = initial account balance
$r$ = annual interest rate as a decimal
$n$ = number of compounding periods per year
 
I tend to prefer not blindly substituting into a formula.

If the interest rate is 7.75% p.a. compounded quarterly, then the quarterly rate is 1.9375%.

So every quarter, you increase by 1.9375%, thus you end up with 101.9375%.

Thus the multiplier is 1.019375

If you're investing for 3 years, then that's 12 quarters.

Thus $\displaystyle A = 50\,000 \times \left(1.019\,375 \right)^{12} $.
 
Even less "blindly": The interest rate is 7.75% annually so 7.75/4= 1.9375% per quarter as Prove It said. That means that after 3 months (one quarter of a year) interest of 50000(0.019375) will be added to the 50000 yielding 50000+ 50000(0.019375)= 50000(1.019375). Since the interest is compounded (neither principle nor interest is collected) quarterly, the next quarter the 1.9375% interest will be calculated on that new 50000(1.019375) so the interest at the end of the second quarter will be (50000(1.019375))(0.019375) and that will be added to the 50000(1.019375) so will be (50000(1.019375))(0.019375)+ 50000(1.019375)= 50000(1.019375)(0.019375+ 1)= 50000(1.0199375)^2.

The third quarter you do the same thing except this time you start with 50000(1.01375)^2 so the interest will be 50000(1.019375)^2(0.019375) added to 50000(1.019375)^2 to get 50000(1.019375)^2(0.019375)+ 50000(1.019375)^2= 50000(1.019375)^2(0.019375+ 1)= 50000(1.019375)^3.

In 3 years there are 3(4)= 12 quarters so you repeat this 12 times getting Prove It's 50000(1.019375)^12.
 

Similar threads

Replies
2
Views
2K
Replies
1
Views
1K
  • · Replies 45 ·
2
Replies
45
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
2
Views
11K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K