Compound Interest: $50000 Invested for 3 Years at 7.75%

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Discussion Overview

The discussion revolves around calculating the amount of money available for sports equipment after investing $50,000 for 3 years at an annual interest rate of 7.75%, compounded quarterly. The focus is on the application of the compound interest formula and the reasoning behind the calculations involved.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • Post 1 presents the initial scenario of the investment and the intended use of the interest earned.
  • Post 2 introduces the compound interest formula, defining the variables involved in the calculation.
  • Post 3 emphasizes a careful approach to applying the formula, calculating the quarterly interest rate and the corresponding multiplier for the investment period.
  • Post 4 elaborates on the compounding process, detailing how interest is calculated on the new balance each quarter and reiterating the formula derived in Post 3.

Areas of Agreement / Disagreement

Participants generally agree on the method of calculating compound interest using the quarterly compounding approach, but there is no explicit consensus on the final amount available for sports equipment, as no numerical results are presented in the discussion.

Contextual Notes

The discussion does not resolve the final numerical outcome, and assumptions regarding the application of the formula and the accuracy of the calculations remain unverified.

kaye
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An alumnus of a local high school donated $50000 to the school. The amount was invested for 3 years at 7.75%, compounded quarterly. The school has agreed to use only the interest earned on the investment to buy sports equipment. How much money will be available for sports equipment at the end of the investments term?
 
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$A = A_0 \left(1 + \dfrac{r}{n}\right)^{nt}$

$A$ = account balance after $t$ years
$A_0$ = initial account balance
$r$ = annual interest rate as a decimal
$n$ = number of compounding periods per year
 
I tend to prefer not blindly substituting into a formula.

If the interest rate is 7.75% p.a. compounded quarterly, then the quarterly rate is 1.9375%.

So every quarter, you increase by 1.9375%, thus you end up with 101.9375%.

Thus the multiplier is 1.019375

If you're investing for 3 years, then that's 12 quarters.

Thus $\displaystyle A = 50\,000 \times \left(1.019\,375 \right)^{12} $.
 
Even less "blindly": The interest rate is 7.75% annually so 7.75/4= 1.9375% per quarter as Prove It said. That means that after 3 months (one quarter of a year) interest of 50000(0.019375) will be added to the 50000 yielding 50000+ 50000(0.019375)= 50000(1.019375). Since the interest is compounded (neither principle nor interest is collected) quarterly, the next quarter the 1.9375% interest will be calculated on that new 50000(1.019375) so the interest at the end of the second quarter will be (50000(1.019375))(0.019375) and that will be added to the 50000(1.019375) so will be (50000(1.019375))(0.019375)+ 50000(1.019375)= 50000(1.019375)(0.019375+ 1)= 50000(1.0199375)^2.

The third quarter you do the same thing except this time you start with 50000(1.01375)^2 so the interest will be 50000(1.019375)^2(0.019375) added to 50000(1.019375)^2 to get 50000(1.019375)^2(0.019375)+ 50000(1.019375)^2= 50000(1.019375)^2(0.019375+ 1)= 50000(1.019375)^3.

In 3 years there are 3(4)= 12 quarters so you repeat this 12 times getting Prove It's 50000(1.019375)^12.
 

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