Compound Interest: Grow $1000 to $1500 in 5 Years?

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Homework Help Overview

The original poster attempts to determine the interest rate required for an investment of $1000 to grow to $1500 over 5 years with quarterly compounding. The problem involves understanding compound interest and logarithmic functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods to solve the equation, including taking the 20th root, using logarithms, and exploring different mathematical tools. Some express confusion over the application of logarithms and roots in the context of the problem.

Discussion Status

Several participants have provided insights and alternative methods for approaching the problem. There is an acknowledgment of different techniques available for solving the equation, but no explicit consensus on a singular method has been reached.

Contextual Notes

Participants note the potential confusion arising from the manipulation of logarithmic expressions and the implications of using different mathematical approaches. There is mention of varying levels of familiarity with logarithms among participants.

kuahji
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At what rate of interest compounded quarterly, to the nearest tenth of a percent, will an investment of $1000 grow to $1500 in 5 years?

I set the problem up 1500=1000(1+x/4)^(4*5)

I then divided by 1000

1.5 = (1+x/4)^20

But this is where I'm stuck.
 
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Well, that's a twentieth degree polynomial.

Just take the 20th root of both sides.
 
Use a logarithm. Get a numerical answer for log(1+x/4). Then exponentiate.
 
Thanks for the replies, I ended up trying that & got

ln 1.5 = 20 ln (1+x/4)

ln1.5/20 = ln (1+x/4)

1+x/4 = e^.02027

x/4 = .02048

x = .08191 or 8.2%

What kept throwing me off was I kept getting the wrong answer because I kept dividing by four. After doing so many of these problems in a row, thought I was getting confused w/what could be done & couldn't be done regarding logarithms. Thanks again for the help.
 
^{20}\sqrt{1.5}=1+x/4 \mbox{ so that } 4^{20}\sqrt{1.5}-4=x

In fact, that's how you can set up a general formula for nominal interest rates.
 
Last edited:
ZioX said:
^{20}\sqrt{1.5}=1+x/4 \mbox{ so that } 4^{20}\sqrt{1.5}-4=x

Yes, it's the same thing.
 
Only because you went around and made exp(.02027)=1.5^(1/20) which was an unnecessary step.

I'm not being adversarial, but the OP should know that there are more tools to use.
 
Last edited:
Thats pretty interesting, I'm in the logarithm section in pre-calc, so that's why they were used. Good to know that there are other ways to solve the problem as well.
 
ZioX said:
Only because you went around and made exp(.02027)=1.5^(1/20) which was an unnecessary step.

I'm not being adversarial, but the OP should know that there are more tools to use.

I'm not disagreeing. The method using logarithms simply dates from an age when taking a twentieth root wasn't an easy thing. The logs are one way to accomplish that (by turning the root into division).
 
  • #10
I just took an actuarial course a couple of semesters ago, and they were able to generate a general formula for variable compounding periods. It utilized mth roots, hence my bias towards them.
 

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