Compute Expectation for $X_{1}^\frac{1}{2}$ with Family $f(x,\theta)$

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The discussion focuses on computing the expectation \(E(X_{1}^{1/2})\) for a random variable \(X_{1}\) with the density function \(f(x,\theta)=\frac{\exp(-\sqrt{x}/\theta)}{2\theta^2}\). The integral for the expectation is expressed as \(E(X_1^{1/2})=\int_0^{\infty} \sqrt{x}\frac{\exp(-\sqrt{x}/\theta)}{2\theta^2}dx\), which simplifies to \(\int_0^{\infty} t^2\frac{\exp(-t/\theta)}{\theta^2}dt\). The challenge arises from the integration by parts approach, which fails due to the non-vanishing derivative of \(\sqrt{x}\).

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Fermat1
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consider a density family $f(x,\theta)=\frac{exp(-{\sqrt{x}}/{\theta})}{2{\theta}^2}$.

Let $X_{1}$ have the density above. Compute $E(X_{1}^\frac{1}{2})$.

Integration by parts doesn't work since the derivative of ${\sqrt{x}}$ never vanishes, so how do I compute the expectation?
 
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Have you got this?

$$E(X_1^{1/2})=\int_0^{\infty} \sqrt{x}\exp(-\sqrt{x}/\theta)/2\theta^2dx=\int_0^{\infty} t^2\exp(-t/\theta)/\theta^2dt$$
 
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Thanks, I'm a bit out of practice with integrals
 

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