Conservation of Energy rollercoaster

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Homework Help Overview

The discussion revolves around the conservation of energy in the context of a roller coaster problem. Participants are examining the total energy at different points of the roller coaster, specifically at point A with a height and point B at ground level, while considering both potential and kinetic energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of potential energy at the top of the roller coaster and the kinetic energy at the bottom. Questions arise regarding the inclusion of kinetic energy at point A and the implications of energy conservation.

Discussion Status

Some participants have pointed out the need to consider both potential and kinetic energy at point A, suggesting that the original poster may have overlooked the initial kinetic energy. There is an exploration of how energy conservation applies to the scenario, with some calculations provided for total energy at both points.

Contextual Notes

Participants are working under the assumption that there is no friction affecting the roller coaster's motion, and they are using a gravitational constant of g=10 m/s². The problem setup includes specific mass and speed values that guide the calculations.

jhrnndz1
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I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?
 
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jhrnndz1 said:
I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?
Aren't you forgetting the initial kinetic energy? HINT: Is energy conserved?
 
Hello jhrnndz1,

you've missed that the roller coaster has kinetic energy at point A as well.

jhrnndz1 said:
A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

Regards,

nazzard
 
jhrnndz1 said:
I have a quetion that I worked out and would love to know if I worked it out alright. Here it goes...

A roller coaster of mass 80kg is moving with a speed of 20.0 m/s at position A with a height of 200m. There is no friction and g=10m/s^2.

So basically there's a diagram of a rollercoaster with different points and different heights.

What is the total energy of the rollercoaster at point A?

So, this is at the top of the rollercoaster, so I basically calculated the potential energy. (mass)*(g)*(height).

Next, what is the total energy of the roller coaster at point B, which has no height.

I calculated the kinetic energy 1/2(mass)(v)^2 and got 1600J

Did I do this correct?

Energy conservation states that total potential + total kinetic = total energy, PE + KE = TE. For your question, TE at point A is 0.5(80)(20)^2 + 80(10)(200) = 176 KJ. At point B, when the roller coaster comes down, its TE is still the same as its PE is converted to KE, thus the roller coaster will have a greater KE, meaning more speed.
 

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