Construction of a probability space.

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Discussion Overview

The discussion revolves around the construction of a probability space, specifically seeking an example that satisfies the condition where if two events have the same probability, they must be identical. The scope includes theoretical aspects of probability spaces and examples of discrete probability distributions.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant proposes a simple probability space with A = {Ω, ∅}, P[Ω] = 1, and P[∅] = 0, questioning its validity.
  • Several participants express agreement with the initial proposal, indicating it looks acceptable.
  • Another participant suggests exploring more complex examples using discrete sets, providing an example with two elements (A, B) where P(A) = 1/3 and P(B) = 2/3.
  • A later reply mentions constructing a similar probability space for a biased coin, indicating a practical application of the concepts discussed.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the initial example, but there are multiple competing views regarding the complexity and applicability of different probability spaces.

Contextual Notes

Some assumptions about the nature of events and their probabilities may not be explicitly stated, and the discussion does not resolve the implications of using more complex probability spaces.

chocolatefrog
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Q. Exhibit (if such exists) a probability space, denoted by (Ω, A, P[·]), which satisfies the following. For A1 and A2 members of A, if P[A1] = P[A2], then A1 = A2.

Answer: A = {Ω, ∅}, P[Ω] = 1 and P[∅] = 0. Is this a valid answer to the above question?
 
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Looks ok to me.
 
haruspex said:
Looks ok to me.

Thank you, haruspex!
 
If you want something more interesting, you can work with discrete sets. Example: 2 elements (A,B) with P(A) = 1/3 and P(B) = 2/3.
 
mathman said:
If you want something more interesting, you can work with discrete sets. Example: 2 elements (A,B) with P(A) = 1/3 and P(B) = 2/3.

Thanks, mathman. I ended up doing something similar; constructed such a space for a biased coin.
 

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