Continuous => limited in region

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SUMMARY

The discussion centers on proving that if a function \( f: \mathbb{R} \to \mathbb{R} \) is continuous at a point \( x' \), then \( f \) is bounded in a neighborhood of \( x' \). The key inequality used is \( |f(a)| \leq |f(a) - f(y)| + |f(y)| \). Participants clarify that "limited in a suitable environment" refers to being "bounded in some neighborhood," which can be established using the epsilon-delta definition of continuity. The proof involves selecting an appropriate \( \epsilon > 0 \) and corresponding \( \delta > 0 \) to demonstrate that \( |f(y)| < M \) for all \( y \) within the neighborhood of \( a \).

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Homework Statement



I've to show that if f:R->R is continuous in x' then f is limited in a suitable environment of x'.

2. The attempt at a solution

My lecturer said we should use the following inequality

|f(a)|=<|f(a)-f(y)|+|f(y)|

But how should I go on, I know I have to show something like this:

It exists d>0: it exist c element of [x'-d, x'+d]=I ==> |f(x)|=<|f(c)| for every x in I.

But how should I go on?
 
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Always include relevant definitions. "limited in a suitable environment" is not standard terminology, and I don't know what it means. It sounds like "bounded in some neighborhood", but this would follow imediately from the epsilon delta definition of continuity.
 
I thought that, too. I mean that it follows imidiately, but our lecturer said that we've to take |f(a)|=<|f(a)-f(y)|+|f(y)| to show that.

With limited in a suitable environment it is ment what you said (bounded in some neightboorhood).
 
Right, so pick any e>0, then a d>0 so that |y-a|<d => |f(y)-f(a)|<e, and then use that inequality to show there is an M with |f(y)|<M, all y in some neighborhood of a.
 

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