Converting ODE to a system of ODEs

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Discussion Overview

The discussion revolves around the conversion of a second-order ordinary differential equation (ODE) into a system of first-order ODEs. Participants explore the correctness of the transformation and the implications for further analysis, such as finding the attraction basin of the system.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes a transformation of the ODE $x''-x+x^3+\gamma x' = 0$ into a system of first-order equations by defining $x_1 = x$ and $x_2 = x'$, leading to the equations $x_1' = x_2$ and $x_2' = x_1 - x_1^3 + \gamma x_2.
  • Another participant suggests that the second equation should actually be $x_2' = x_1 - x_1^3 - \gamma x_2$, indicating a potential error in the initial formulation.
  • A later reply acknowledges the typo and expresses interest in finding the attraction basin for the system, indicating a shift towards exploring the system's dynamics.
  • There is a reference to another resource regarding the damping coefficient, suggesting a connection to broader discussions on system behavior.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct formulation of the second equation, as one participant identifies a potential error. The discussion remains unresolved regarding the implications of this correction on the analysis of the system.

Contextual Notes

The discussion includes a correction to the mathematical formulation, but the implications of this correction on the overall analysis of the system's behavior are not fully explored. There are also references to external resources that may provide additional context.

Who May Find This Useful

Readers interested in the conversion of higher-order ODEs to systems of first-order ODEs, as well as those exploring dynamical systems and their stability properties, may find this discussion relevant.

Dustinsfl
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Given $x''-x+x^3+\gamma x' = 0$.

Is the below correct? Can I do this? The answer is yes.

Let $x_1 = x$ and $x_2 = x'$. Then $x_1' = x_2$.
\begin{alignat}{3}
x_1' & = & x_2\\
x_2' & = & x_1 - x_1^3 + \gamma x_2
\end{alignat}

Then I have the above linear system from the given ODE.
 
Last edited:
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dwsmith said:
Given $x''-x+x^3+\gamma x' = 0$.

Is the below correct? Can I do this? The answer is yes.

Let $x_1 = x$ and $x_2 = x'$. Then $x_1' = x_2$.
\begin{alignat}{3}
x_1' & = & x_2\\
x_2' & = & x_1 - x_1^3 + \gamma x_2
\end{alignat}

Then I have the above linear system from the given ODE.

Second equation should be
$$x_{2}'=x_{1}-x_{1}^{3}-\gamma x_{2}.$$
 
Ackbach said:
Second equation should be
$$x_{2}'=x_{1}-x_{1}^{3}-\gamma x_{2}.$$

Thanks typo. I trying to find the attraction basin for this system in another post. Are you familiar with that stuff?
 
dwsmith said:
Thanks typo. I trying to find the attraction basin for this system in another post. Are you familiar with that stuff?

I think your question is answered http://www.mathhelpboards.com/f17/damping-coefficient-2045/.
 

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