Convolution theorem and laplace transforms

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SUMMARY

The convolution theorem states that the Laplace transform of the convolution of two functions is the product of their individual Laplace transforms. Specifically, if laplace(f) = F(s) and laplace(g) = G(s), then laplace(f * g) = F(s) * G(s). However, the inverse Laplace transform of the product F(s) * G(s) requires integration to obtain the convolution result f * g. This indicates that convolution is not a straightforward multiplication operation, but rather a more complex process that involves integration.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with convolution operations
  • Basic calculus skills
  • Knowledge of inverse Laplace transforms
NEXT STEPS
  • Study the properties of Laplace transforms in detail
  • Learn about convolution in the context of signal processing
  • Explore the application of the convolution theorem in differential equations
  • Practice solving problems involving inverse Laplace transforms
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Students of engineering, mathematicians, and anyone studying control systems or signal processing who seeks to understand the convolution theorem and its applications in Laplace transforms.

indianaronald
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Okay, so this is the first time I'm encountering this theorem and I'm not very strong in calculus. But I tried to understand it myself but couldn't.

Convolution theorem is the one in the attachment as give in the book ( couldn't find a way to type that out easily). My doubt is if laplace(f) = F(s) and laplace(g) = G(s) and laplace( f*g )= F(s)*G(s), why not
laplace-inverse[ F(s)*G(s) ]=f*g, which is given but why do the integration at all after that? ( but my answers don;t match if I do it this way; that is without that final integration so I'm obviously misunderstanding it)

Thank you very much for any help.
 

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Damn. I understand. What is there to understand anyway? It is not really multiplication at all. The symbol stands for 'convolution'. I can't delete this thread. So umm...it's going to be my beacon of stupidity, I guess, thank you very much.
 

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