- #1
robousy
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Hey folks,
I'm writing a pop-sci article for a journal and one of the referees wants me to give the cosmological const in mks units instead of GeV. I just wanted to check with anyone in the know if the following looks correct.
First, the accepted value of lambda (order of mag):
[tex]\Lambda=10^{-47}(GeV)^4[/tex]
I want to convert this to [itex]J/m^3[/itex]
The following website http://hep.uchicago.edu/~dkrop/Natural_Units_Conversions.html [Broken] gives the conversion from meters to GeV
[tex]1m=5.07\times 10^{15}GeV[/tex]
so I can convert lambda to GeV/m^3
[tex]\Lambda=\frac{10^{-47}GeV^4}{(5\times 10^{-15}GeV)^3}=8\times 10^{-2}GeV/m^3[/tex]
Finally the website gives conversion from GeV to Joules
[tex] 1 J=7 \times 10^{9}GeV[/tex]
So,
[tex]\Lambda=\frac{8\times 10^{-2}GeV/m^3}{1 \times 10^{9}GeV}\approx 10^{-10} J/m^3[/tex]
Has anyone performed this conversion before?
Does this figure of [itex]\Lambda[/itex] look correct?
Thanks in advance!
I'm writing a pop-sci article for a journal and one of the referees wants me to give the cosmological const in mks units instead of GeV. I just wanted to check with anyone in the know if the following looks correct.
First, the accepted value of lambda (order of mag):
[tex]\Lambda=10^{-47}(GeV)^4[/tex]
I want to convert this to [itex]J/m^3[/itex]
The following website http://hep.uchicago.edu/~dkrop/Natural_Units_Conversions.html [Broken] gives the conversion from meters to GeV
[tex]1m=5.07\times 10^{15}GeV[/tex]
so I can convert lambda to GeV/m^3
[tex]\Lambda=\frac{10^{-47}GeV^4}{(5\times 10^{-15}GeV)^3}=8\times 10^{-2}GeV/m^3[/tex]
Finally the website gives conversion from GeV to Joules
[tex] 1 J=7 \times 10^{9}GeV[/tex]
So,
[tex]\Lambda=\frac{8\times 10^{-2}GeV/m^3}{1 \times 10^{9}GeV}\approx 10^{-10} J/m^3[/tex]
Has anyone performed this conversion before?
Does this figure of [itex]\Lambda[/itex] look correct?
Thanks in advance!
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