- #1

karush

Gold Member

MHB

- 3,269

- 5

From the periodic Formula $\tan{(\theta+\pi n)}=\tan{\theta}$

thus

$

\displaystyle

\cot{(\theta)}

=\tan{(2\theta)}

\Rightarrow

\frac{1}{\tan{\theta}}

=\tan{(2\theta)}

$

there are 6 answers to this, but stuck here