How Many 3-Letter Arrangements of aabbcccdddd Are Possible?

Click For Summary

Discussion Overview

The discussion revolves around calculating the number of distinct 3-letter arrangements that can be formed from the letters in "aabbcccdddd." Participants explore different methods for counting arrangements based on the frequency of each letter.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant initially presents the problem and suggests that the total arrangements using all letters would be calculated using the formula 11!/(2!2!3!4!), but seeks clarification for using only 3 letters.
  • Another participant proposes a method involving counting permutations with one letter of each type, permutations with one letter appearing twice and another appearing once, and specifically mentions arrangements for "ccc" and "ddd."
  • There is a calculation disagreement where one participant suggests the total arrangements equal 52, while another claims it is 62 after re-evaluating their calculations.
  • Participants express uncertainty about the accuracy of their calculations and engage in checking each other's results.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the final count of arrangements, with differing results of 52 and 62 being presented without resolution.

Contextual Notes

Participants' calculations depend on the interpretation of how to select and arrange the letters, and there may be missing assumptions regarding the specific combinations considered.

ashi_mashi
Messages
8
Reaction score
0
hi everyone...
how many arrangements of this word "aabbcccdddd" is possible if we only use 3 of them? I know if we could use all of them it would just be 11!/(2!2!3!4!), but what if we only use 3? :confused:

Thanks in advance
 
Physics news on Phys.org
I assume you mean 3 letters in the arrangement. First count the number of ways to permute using 1 letter of each, then in addition to that count the number of ways to permute using 1 of one letter and 2 of another, and then add 2 for the arrangements ccc and ddd.
 
ok..thanks...so the answer would be 52?
 
Not quite what I got--maybe you added wrong at the end?
 
umm...i tried it again...i got 62 (checked it 3 times!)
 
Yep, 62 is what I got. You said 52 the other time.
 
thanks a lot
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K