MHB Creating an absolute value equation from an inequallity

Click For Summary
To create an absolute value equation from the inequality -6 ≤ x ≤ 14, first recognize that this can be expressed in terms of absolute value. By subtracting 4 from each part of the inequality, you derive -10 ≤ x - 4 ≤ 10. This leads to the absolute value equation |x - 4| ≤ 10. Additionally, the general formula for converting an interval a ≤ x ≤ b into absolute value form is |x - (a + b)/2| ≤ (b - a)/2, which reinforces the derived equation. Understanding these transformations clarifies how to represent inequalities using absolute values effectively.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
if you are given $$-6 \leq x \leq 14$$

from this how do you create an abs equation like $$|x-4| \leq 10$$

k
 
Mathematics news on Phys.org
Re: creating an abs equation

karush said:
if you are given $$-6 \leq x \leq 14$$

from this how do you create an abs equation like $$|x-4| \leq 10$$

k

Note that we can express the absolute value in terms of an inequality: $|y|\leq c \iff -c \leq y \leq c$.

Now, note that if we subtract 4 from each piece of $-6\leq x\leq 14$, we get $-10\leq x-4 \leq 10$. Thus, by what I mentioned in the first line, this means that $|x-4|\leq 10$.

Does this clarify things?
 
Re: creating an abs equation

karush said:
if you are given $$-6 \leq x \leq 14$$
from this how do you create an abs equation like $$|x-4| \leq 10$$

a \le x \le b converts to \left| {x - \frac{{a + b}}{2}} \right| \le \frac{{b - a}}{2}.

Think of the mid-point of [a,b] as well as the radius.
 
Thread 'Erroneously  finding discrepancy in transpose rule'
Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K