Current ratio for wire with variable drift speed vs constant drift speed

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Winzer
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Homework Statement


The diagram shows two wires; wire 1 and wire 2. The charge carriers in wire 1 (of circular cross section and radius R) have a drift speed down the wire that is not constant across the wire. Instead, the drift speed rises linearly from zero at the circumference (r=R) to at the center (r = 0), according to vd1(r)=Vo(1-(r/R)).The second wire (wire 2) has the same radius, the same density of charge carriers and a constant drift speed given by vd1(r)= fVo. Evaluate the ratio of the current carried by wire 2 to the current carried by wire 1, when f = 0.490.

Homework Equations


[tex]I=nqAV_{d}[/tex]

[tex]\frac{qnAV_{d2}}{qnAV_{d1}}[/tex]

The Attempt at a Solution


So since q,n,A are the same they cancel leaving:
[tex]\frac{I_{2}}{I_{1}}= \frac{V_{d2}}{V_{d1}}[/tex]
I need to find vd now.
 
Attachments
  • Diagram of two cylindrical wires labelled WIRE 1 and WIRE 2, each with radius R marked on its end face. In WIRE 1, arrows show drift speed v0 at the edge, decreasing to v0(1-r/R) at radius r. In WIRE 2, two arrows of equal length are labelled fv0.
    TwoWireComparison1.jpg
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Last edited:
To find current in first wire you need to integrate. Sice speed is constant at fixed r you should write: [tex]dI=nqv(r)2\pi rdr[/tex] and then integrate.

Hope you understand why, else ask.