- #1

roldy

- 237

- 2

- Homework Statement
- What is the deflection of a fixed 40' beam that is rotated 90 degrees so that the flanges are vertical with a loading of a 40' long 18" diameter pipe filled with water? The beam is W14 x 30

- Relevant Equations
- V=A*L

A=pi*D^2/4

m=rho*V

W=m*g

I=1/12 * b*h^3

deflection = wL^3/(24EI)

__W14 x 30:__

d = 13.84" = 0.352 m

w = 6.730" = 0.171 m

t

_{w}= 0.270 = 0.00686 m

t

_{f}= 0.385 = 0.00978 m

40' = 12.192 m

18" = 0.4572 m

ρ = 997 kg/m

^{3}

E = 1.4*10

^{9}

__Calculate Weight of water:__

V = A*L = π*(0.4572)

^{2}/4 *12.192 = 2.0016m

^{3}

W = m*g = ρ*V*g = 997*2.0016*9.81 = 19.576kN uniformally distributed load

__Calculate moment of inertia of beam:__

I = 1/12*b*h

^{3}= I

_{flanges}+ I

_{inside}= 2*[1/12*0.00978*0.352

^{3}] + [1/12*(0.352-0.00978)*0.00686

^{3}] = 7.1099*10

^{-5}m

^{4}

__Calculate deflection of beam:__

δ = wL

^{3}/(24EI) = 19.576*12.192

^{3}/(24*1.4*10

^{9}*7.1099*10

^{-5}) = 0.149 m

Is my process correct? I've never done a rotated I-beam before.