Degree of a Map: Directly Proving k is Degree of f

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SUMMARY

The discussion focuses on proving that the degree of the continuous mapping f: S1 -> S1, defined as f(x) = (cos(2πx), sin(2πx)) to f(x) = (cos(2kπx), sin(2kπx)), is equal to k using homological definitions. Participants emphasize the need to avoid using Hurewicz's theorem and instead rely on fundamental properties of continuous mappings on circles. The conversation references the Wikipedia page on the degree of a continuous mapping for foundational insights.

PREREQUISITES
  • Understanding of continuous mappings in topology
  • Familiarity with homological algebra concepts
  • Knowledge of the properties of the unit circle S1
  • Basic understanding of degree theory in topology
NEXT STEPS
  • Study the homological definition of degree in topology
  • Explore the properties of continuous mappings on S1
  • Review the implications of the Hurewicz theorem in homology
  • Examine examples of degree calculations for various continuous functions
USEFUL FOR

Mathematicians, topologists, and students studying algebraic topology who are interested in understanding the degree of continuous mappings and their proofs without relying on advanced theorems.

wineesarne
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Consider f: S1 -> S1: (cos 2 pi x, sin 2 pi x) -> (cos 2 k pi x, sin 2 k pi x).

How to show directly from the homological definition (without using Hurewicz etc) that degree(f) = k?
 
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