A bar suspended in air weighs 1.75 N
The same bar weigs only 1.4 N when suspended in water.
b. density of the bar
D = m/v
F = m*a
The Attempt at a Solution
Upthrust is 1.75 N - 1.4 N = 0.35 N
Assuming density of water is 1x103 kg m-3
and weight of bar displaces that amount of water.
volume 1.75 N of water = 1.75 N / (1x103 * g) = 1.78 m3
Density of bar = m/v = 1.75 N / 1.78 m3 = 0.98 N m-3
which has to be wrong, surely, or the bar would float . . .