Density. Please explain this solution

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The problem involves a sphere submerged in water, tethered to the bottom, with the tension in the string being one-third of the sphere's weight. To find the density of the sphere, the relationship between the tension, the weight of the sphere, and the weight of the displaced water is crucial. The tension can be expressed as the weight of the sphere minus the weight of the water displaced, which is calculated using the sphere's volume and the density of water. The volume of the sphere is determined using the formula for the volume of a sphere, 4/3 π r^3. Understanding these relationships helps clarify the solution to the problem.
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Homework Statement


A sphere completely submerged in water is tethered to the bottom with a string. The tension in the string is one-third the weight of the sphere.

What is the density of the sphere


Homework Equations



Here is the solution to this problem. It is problem 15.17, the second one on the page. I understand the first line, but for the second line of equations, I have no idea where these equations are coming from. Can someone please explain the second line of equations?
http://www.phy-astr.gsu.edu/Hsiao-Ling/Homework10.pdf

The Attempt at a Solution



Solution is in the link, just need help understanding it
 
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They are mostly about the volume of a sphere.
The tension in the string = weight of sphere - weight of water displaced
The weight of the water is = volume of water * density of water * g
The volume is found from the volume of a sphere ( 3/4 pi r^3 )
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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