Derivation in bohm's Quantum Theory

  • Thread starter A_B
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  • #1
A_B
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halfway page 41 Bohm obtains for the action variable
[tex]
J = 2\int_{a(E)}^{b(E)} dq \sqrt{2m[E-V(q)]}
[/tex]
Then he obtians the partial derivative to E "by a well-known theorem of the calculus":

[tex]
\frac{\partial J}{\partial E} = 2\left\{ \sqrt{2m\left[E-V(q)\right]} \right\}_{q=b} \frac{\partial b}{\partial E} - 2\left\{ \sqrt{2m[E-V(q)]} \right\}_{q=a} \frac{\partial a}{\partial E} + 2 \int_a^b \sqrt{\frac{m}{2[E-V(q)]}} dq.
[/tex]

What is this "well-known theorem"?

Thanks,
A_B
 

Answers and Replies

  • #3
A_B
93
1
thanks! ...Never came across that one before...

A_B
 

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