Derive Equation for Velocity as Function of Time - Help Integrating

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Homework Help Overview

The original poster attempts to derive an equation for an object's velocity as a function of time, starting from an acceleration equation related to mass and a constant. The discussion involves integrating to find velocity, with a focus on the relationship between velocity, mass, and time.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the integration of the equation involving velocity and acceleration, with some suggesting the use of natural logarithms and exponentiation. There is also a consideration of the implications of the constants involved and their units.

Discussion Status

Participants are actively engaging with the mathematical steps involved in the integration process. Some have provided guidance on the integration of logarithmic functions, while others express concerns about the physical meaning of the constants and the units involved. Multiple interpretations of the problem are being explored.

Contextual Notes

There is mention of specific variables such as the mass of fuel and its relation to the velocity of an object, indicating that the problem may involve varying mass over time. The original poster's equation and assumptions about constants are also under discussion.

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Homework Statement


Derive an equation for an objects velocity as a function of time


Homework Equations



i have that a=-(kvo/m)

The Attempt at a Solution


so i get dv/v=-(k/m)dt then i get
1/v= -kt/m +C and then I am stuck
 
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It's been awhile, but I think the integral of dv/v is the natural log of v. Then you can probably exponentiate both sides
 
so
lnv= ln(-kt/m +C)
then
e^lnv=e^ln(-kt/m +C)
so is this right
v=e^ln(-kt/m +C)
 
you only have the 1/v on the left side:

lnv= (-kt/m +C)

e^lnv=e^(-kt/m +C)
so is this right
v=e^(-kt/m +C)

yeah, that seems about right. I'm a little worried about the units, maybe you can do something with that k or C...
 
a=-(kvo/m)
The above relation represent rocket equation where vo represents the velocity of escaping of gas which is constant an k represents dm/dt, the mass of fuel ejected per unit time. It is also constant. Here mass of the fuel is varying with time.
So you can find the velocity of the object with respect to mass rather than the time.
a = dv/dt = - (dm/dt)vo/m
dv = -vo(dm/m). To find the velocity take the integration between the limits m = Mo to m = M.
 

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