Graduate Deriving Equality with Binomials

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SUMMARY

The discussion centers on deriving the equality presented in Lemma 2.1 of the paper "Eigenvalues of Large Random Graphs" by S. J. Miller. The equality involves a summation of binomial coefficients and is expressed as: \sum_{k=1}^s\binom{2s-k}{s}\frac{k}{2s-k}v^k(v-1)^{s-k}=v\sum_{k=0}^{s-1}\binom{2s}{k}\frac{s-k}{s}(v-1)^{k}. Participants suggest expanding the terms (v-1)^{n} and applying binomial addition theorems, with a recommendation to use induction on s for simplification.

PREREQUISITES
  • Understanding of binomial coefficients and their properties
  • Familiarity with mathematical induction techniques
  • Knowledge of polynomial expansion, specifically the binomial theorem
  • Basic comprehension of summation notation and series
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LuHell
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Hi,

I am reading a paper and I am trying to understand an equality which is given without proof:
\sum_{k=1}^s\binom{2s-k}{s}\frac{k}{2s-k}v^k(v-1)^{s-k}=v\sum_{k=0}^{s-1}\binom{2s}{k}\frac{s-k}{s}(v-1)^{k}
Here, s>0, k and v are positive integers.
The equality in question appears in Lemma 2.1 of
http://web.williams.edu/Mathematics.../graphs/mckay_EigenvalueLargeRandomGraphs.pdf

Would you be kind and give me some insights on how to derive this equality?

Thank you,

LH
 
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I'm afraid you will have to expand the terms ##(v-1)^{n}## and some addition theorems on binomials. Perhaps an induction on ##s## can shorten the way.
 

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