Deriving Moment & Elastic Curve Equations for Incomplete Triangular Load on Beam

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SUMMARY

The discussion focuses on deriving the moment and elastic curve equations for an incomplete triangular load on a simply supported beam with a pin at one end and a roller at L/2. The triangular load is defined as a distributed load that starts at zero at the pin and increases linearly to the roller. The deflection equations provided are Δ = Δ(x) for x ≤ L/2 and Δ = θ2*(x-L/2) for x ≥ L/2, where Δ(x) and θ2 are specific functions related to the beam's deflection and slope. This derivation is crucial for accurately analyzing beam behavior under non-uniform loading conditions.

PREREQUISITES
  • Understanding of beam theory and mechanics of materials
  • Familiarity with the concepts of distributed loads and support reactions
  • Knowledge of deflection and slope equations for beams
  • Proficiency in using mathematical derivations in structural analysis
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  • Study the derivation of moment equations for various loading conditions on beams
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  • Explore advanced topics in beam deflection, including the use of the Euler-Bernoulli beam theory
  • Investigate numerical methods for analyzing beams under complex loading scenarios
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Structural engineers, civil engineering students, and anyone involved in the analysis and design of beams under varying load conditions will benefit from this discussion.

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I was wondering how you would derive the moment and elastic curve equations for an incomplete triangular load. Say you have a pin at the left end of the beam and a roller at L/2 from the left, and a triangular load that goes from the pin and ends at the roller. I know you have to do some kind of extension, but how do you come up with the formula.
 
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When you say "triangular load", you mean a distributed load that's zero at the left end and increases linearly to the roller at L/2?
 
If you know Δ(x) and θ2 for a simply supported beam as a function of L' = L/2 with a triangular load then the deflection would be:

Δ = Δ(x) for x=<L/2
= θ2*(x-L/2) for x>=L/2
 
Last edited:
@timthereaper yes
 

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