Deriving the constant e using a sequence limit

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Fibo's Rabbit
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Homework Statement


Why does lim( (1+(1/n))^n ) = e?

Homework Equations


If a_n convergent to a, and b_n converges to b, then (a_n * b_n) converges to (a * b)

The Attempt at a Solution



The lim(1 + (1/n)) = 1.

If you multiply (1 + (1/n)) by itself n-times, you get the equation (1 + (1/n))^n, so according to the statement under Relevant equations above, shouldn't the answer be 1^n, or just 1?

Obviously it is e, b/c when you plug (1 + (1/n))^n into your calculator for larger values of n, you get closer and closer to e.
 
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Hi Fibo's Rabbit! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)
Fibo's Rabbit said:
If a_n convergent to a, and b_n converges to b, then (a_n * b_n) converges to (a * b)

ah, but that only applies for the product of a fixed number of series …

you're trying to apply it to an infinitely increasing number of series :wink:
 
Ah, and it all makes a lot more sense now.